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	<title>Comments on: Atmega8 breadboard circuit &#8211; Part 1 of 3 &#8211; Power supply</title>
	<atom:link href="http://www.protostack.com/blog/2009/07/atmega8-breadboard-circuit-part-1-of-3-power-supply/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.protostack.com/blog/2009/07/atmega8-breadboard-circuit-part-1-of-3-power-supply/</link>
	<description>Atmega168 development kits, AVR Development boards, Prototyping boards and Electronic components</description>
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		<title>By: protostackadmin</title>
		<link>http://www.protostack.com/blog/2009/07/atmega8-breadboard-circuit-part-1-of-3-power-supply/#comment-11211</link>
		<dc:creator>protostackadmin</dc:creator>
		<pubDate>Thu, 22 Sep 2011 22:41:07 +0000</pubDate>
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		<description>Yeah, 150 ohm is a bit low.</description>
		<content:encoded><![CDATA[<p>Yeah, 150 ohm is a bit low.</p>
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	<item>
		<title>By: Nico</title>
		<link>http://www.protostack.com/blog/2009/07/atmega8-breadboard-circuit-part-1-of-3-power-supply/#comment-11166</link>
		<dc:creator>Nico</dc:creator>
		<pubDate>Thu, 22 Sep 2011 07:57:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.protostack.com/blog/?p=42#comment-11166</guid>
		<description>I think you should drive your LED with less current to preserve your 9V battery.
A 680R resistor would give the LED around ??mA which should be enough to make it sufficiently visible.
(VOLTAGEsuppy - VOLTAGEforward-drop-led)/5.5mA = +/-680R</description>
		<content:encoded><![CDATA[<p>I think you should drive your LED with less current to preserve your 9V battery.<br />
A 680R resistor would give the LED around ??mA which should be enough to make it sufficiently visible.<br />
(VOLTAGEsuppy &#8211; VOLTAGEforward-drop-led)/5.5mA = +/-680R</p>
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